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Or # Tangent Line Calculator

Select the parabola equation type and write its value along with the point. The calculator will instantly determine the tangent line equation touching at a specified point.

Choose Type:

Enter a function: f(x)

y(t)

Enter a point: (x₀)

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An online tangent line calculator will help you to determine the tangent line to the implicit, parametric, polar, and explicit at a particular point. Apart from this, the equation of tangent line calculator can find the horizontal and vertical tangent lines as well.

## What is a Tangent Line?

The line and the curve intersect at a point, that point is called tangent point. So, a tangent is a line that just touches the curve at a point. The point where a line and a curve meet is called the point of tangency. ### Tangent Line Formula

Well, there are various variables used to determine the equation of the tangent line to the curve at a particular point:

• The slope of a tangent line
• On the curve, where the tangent line is passing

So the Standard equation of tangent line:

$$y – y_1 = (m)(x – x_1)$$

Where (x_1 and y_1) are the line coordinate points and “m” is the slope of the line.

Example:

Find the tangent equation to the parabola x_2 = 20y at the point (2, -4):

Solution:

$$X_2 = 20y$$

Differentiate with respect to “y”:

$$2x (dx/dy) = 20 (1)$$

$$m = dx / dy = 20/2x ==> 5/x$$

So, slope at the point (2, -4):

$$m = 4 / (-4) ==> -1$$

Equation of Tangent line is:

$$(x – x_1) = m (y – y_1)$$

$$(x – (-4)) = (-1) (y – 2)$$

$$x + 4 = -y + 2$$

$$y + x – 2 + 4 = 0$$

$$y + x + 2 = 0$$

When using slope of tangent line calculator, the slope intercepts formula for a line is:

$$x = my + b$$

Where “m” slope of the line and “b” is the x intercept.

So, the results will be:

$$x = 4 y^2 – 4y + 1 at y = 1$$

Result = 4

Therefore, if you input the curve “x= 4y^2 – 4y + 1” into our online calculator, you will get the equation of the tangent: $$x = 4y – 3$$.

### Determining the Equation of a Tangent Line at a Point

Determine the equation of tangent line at y = 5.

Solution:

$$f (y) = 6 y^2 – 2y + 5f$$

First of all, substitute y = 5 into the function:

$$f (5) = 6 (5)^2 – 2 (5) + 5$$

$$f (5) = 150 – 10 + 5 ==> f (5) = 165$$

by taking the derivative and plug in y = 5:

$$f ‘ (y) = 12y – 2$$

$$f ‘(5) = 12 (5) – 2$$

$$f ‘ (5) = 58$$

Then, add both f (5) and f'(5) into the equation of a tangent line, along with 5 for a:

$$y = 93 + 46 (y – 5)$$

so the result will be:

$$x = 93 + 46y – 184$$

$$x = 46y – 91$$

## How Tangent Line Equation Calculator Works?

### Input:

• Firstly, choose the type of curve either explicit, parametric, or polar from the drop-down list.
• Now, Enter the values of the function
• Then, enter a particular point where you want to find a tangent line
• Click the calculate

### Output:

• Then find the function and take the derivative of a certain function
• Lastly, the calculator determines the slope and the tangent line

## FAQs:

### Why should we Search Tangent of Function Graphs?

To find a tangent to a graph in a point, we can say that a certain graph has the same slope as a tangent. Then use the tangent to indicate the slope of the graph.

### Is Slope of a Tangent Line the Derivative?

The derivative of a function gives the slope of a line tangent to the function at some point on the graph. This will be used to find the equation of a tangent line.

## Reference:

From the source of Wikipedia: Tangent line to a curve, Analytical approach, Intuitive description.

From the source of Krista King: What Is The Tangent Line, the tangent line at a particular point, Equation Of The Tangent Line.