Enter the values to calculate the Taylor series representation of a function.
Use this Taylor Series Calculator to represent any function as a Taylor series step by step. You can expand the function by specifying:
x = 0.Limitation: This calculator is suitable for representing the Taylor series. It cannot analyze convergence or explore alternative series representations.
The Taylor series is an infinite sum of terms derived from a function’s derivatives at a specified point. It is widely used in calculus to approximate the values of complex functions near the chosen point. By representing complex functions as polynomials, computations become simpler and more manageable.
The general formula for a Taylor series expansion of a function f(x) around a point a is:
\( f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!} (x - a)^n = f(a) + f'(a)(x - a) + \frac{f''(a)}{2!} (x - a)^2 + \frac{f'''(a)}{3!} (x - a)^3 + \dots \)
You can specify the degree n in the calculator to get a finite approximation. A higher degree generally improves the accuracy of the approximation.
Find the Taylor series of f(x) = √(x² + 4) up to degree n = 2 at the point x = 1.
Solution:
Taylor series formula:
\( f(x) \approx P(x) = \sum_{k=0}^{2} \frac{f^{(k)}(a)}{k!} (x - a)^k \)
Step 1: Zeroth derivative
\( f(x) = \sqrt{x^2 + 4}, \quad f(1) = \sqrt{5} \)
Step 2: First derivative
\( f'(x) = \frac{x}{\sqrt{x^2 + 4}}, \quad f'(1) = \frac{1}{\sqrt{5}} \)
Step 3: Second derivative
\( f''(x) = \frac{4}{(x^2 + 4)^{3/2}}, \quad f''(1) = \frac{4}{5√5} = \frac{4√5}{25} \)
Step 4: Construct the polynomial
\( P(x) = f(1) + f'(1)(x - 1) + \frac{f''(1)}{2!}(x - 1)^2 \)
Step 5: Substitute values and simplify
\( P(x) = \sqrt{5} + \frac{\sqrt{5}}{5} (x - 1) + \frac{2 \sqrt{5}}{25} (x - 1)^2 \)
Wikipedia: Taylor Series
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