Find the heat energy of any substance by using the Q = m.c.ΔT equation. Also, you can calculate values for specific heat, mass, or temperature change.
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This Specific Heat Calculator finds the heat energy, specific heat capacity, mass, or temperature change of a substance. It uses the heat transfer equation to determine any missing value when the other variables are known. The calculator also helps users understand how these variables are related and provides a clear, step-by-step breakdown of the calculation. With this tool, solving specific heat problems becomes easier and more straightforward.
Specific heat is the amount of heat energy required to raise the temperature of a unit mass of a substance (such as 1 gram or 1 kilogram) by 1 degree Celsius or 1 Kelvin.
Note: The temperature should change without changing the substance's state. For Example, when heating water, it should remain a liquid and not boil.
The specific heat formula is:
Q = m × c × ΔT
Formula Parts
The heat transfer equation can be rearranged in different ways to calculate any unknown parameter. Here are the rearranged formulas:
▸ To find the specific heat capacity (c):
c = Q / (m × ΔT)
▸ To find the mass (m):
m = Q / (c × ΔT)
▸ To find the change in temperature (ΔT):
ΔT = Q / (m × c)
To use this online calculator, follow the simple steps below:
Optional: Select a substance to find its standard specific heat capacity.
To calculate the specific heat of a substance, follow the given steps:
Step 1: Find the Heat Energy (Q)
Find how much energy the substance absorbed (+ Q) or lost (- Q)
For Example: Let’s suppose a 50 g piece of an unknown metal absorbs 350 J of heat as its temperature rises from 20°C to 50°C.
Since the metal absorbs heat, the heat energy is positive. Q = 350 J
Step 2: Find the Mass (m)
Weigh the sample to get its total mass in grams or kilograms.
The sample's mass is given as m = 50 g
Step 3: Calculate the Temperature Change (ΔT)
Subtract the initial temperature from the final: (ΔT = Tf − Ti)
A positive ΔT means the substance warmed up, and a negative ΔT means it cooled down.
The temperature rises from 20°C to 50°C, so change in temperature will be:
ΔT = 50°C − 20°C
ΔT = 30°C
Step 4: Solve for Specific Heat
Multiply mass by temperature change, then divide the heat energy (Q) by that result, as:
c = Q / (m · ΔT)
= 350 / (50 · 30)
= 350 / 1500
≈ 0.233 J/(g·°C)
If you have a specific problem to solve, just enter your known values into this specific heat capacity calculator, and let it calculate the answer for you.
The following table provides specific heat capacity values of common materials.
| Substance / Material | Specific Heat (J/kg·K) | Substance / Material | Specific Heat (J/kg·K) |
|---|---|---|---|
| Acetals (Solid) | 1500 | Air (Gas (Room conditions)) | 1005 |
| Air (Sea level - dry (0°C)) | 1003 | Aluminum (Solid) | 900 |
| Ammonia (Liquid) | 4700 | Animal tissue (Mixed) | 3500 |
| Antimony (Solid) | 210 | Argon (Gas) | 520 |
| Arsenic (Solid) | 330 | Asphalt | 920 |
| Beryllium | 1825 | Bismuth | 122 |
| Brick | 840 | Cadmium | 232 |
| Carbon Dioxide (Gas) | 846 | Chromium (Solid) | 448 |
| Concrete | 880 | Copper | 385 |
| Diamond | 509 | Ethanol (Liquid) | 2440 |
| Gasoline (octane) | 2220 | Glass (Solid) | 840 |
| Glass, crown | 670 | Glass, flint | 503 |
| Glass, pyrex | 753 | Gold | 129 |
| Granite | 790 | Graphite | 710 |
| Gypsum | 1090 | Helium (Gas) | 5193 |
| Hydrogen | 14300 | Hydrogen sulfide | 1015 |
| Iron | 450 | Lead (Solid) | 128 |
| Lithium | 3582 | Lithium (at 181°C) | 4178 |
| Magnesium (Solid) | 1023 | Marble, mica | 880 |
| Mercury (Liquid) | 140 | Methane (at 2°C) | 2220 |
| Methanol (Liquid) | 2530 | Molten salt (Liquid) | 1500 |
| Neon (Gas) | 1030 | Nitrogen (Gas) | 1040 |
| Oxygen (Gas) | 918 | Paraffin wax (Solid) | 2100 |
| Polyethylene | 2300 | Sand | 830 |
| Silica (fused) | 703 | Silver | 235 |
| Sodium | 1230 | Soil | 1300 |
| Steel | 490 | Tin | 228 |
| Titanium | 523 | Tungsten | 134 |
| Uranium | 116 | Water (ice, at -10°C) | 2108 |
| Water (at 25°C) | 4184 | Water (at 100°C) | 2080 |
| Wood (1200 to 2900) | 1700 | Zinc (Solid) | 388 |
This is a specific heat equation that calculates the heat energy transferred (Q) during a temperature change without changing its physics state.
It can’t handle the phase changes as it works based on the specific heat capacity formula Q = m c ΔT. This formula applies to the temperature changes within a single physical state.
ΔT can either be a unit of temperature in °C or K, because a temperature change in °C is numerically identical to a temperature change in 1 K.
To find the temperature change in a specific heat calculation, divide the heat energy by the product of mass and specific heat capacity. The formula is:
ΔT = q / m x c
The specific heat capacity of water is approximately 4.184 J/g°C (or 4,184 J/kg·K).
No, specific heat capacity is always a positive value as it indicates the rise of temperature in per unit mass of a substance. So specific heat energy is always positive regardless of whether the energy is being added or removed.
The most common metric units used for the specific heat capacity are Joules per gram per degree Celsius (J/g°C) or Joules per kilogram per Kelvin (J/kg·K).
For more details, see Specific Heat Capacity - Wikipedia.
britannica.com - Specific-Heat.
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