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Select the parameter and enter the required values and then find the specific heat, heat energy, mass of substance, initial temperature, and final temperature of the substance.

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The specific heat calculator helps to find the specific heat, heat energy, mass of substance, initial temperature, and final temperature of any substance. When it comes to analyzing the specific heat of the water or any other substance, it tells us the specific heat formula along with the whole solution for a respective substance.

It is the amount of heat that is required to change the temperature of a mass unit of any substance only by one degree. To find the specific heat capacity, we can say that it is a measure of the total energy that is needed to heat up 1 kilogram of any material to 1°Celcius or 1Kelvin. These phenomena should take place within a temperature range, where the substance doesn't change its state e.g. In the case of water, it shouldn’t get boiled.

The heat capacity formula is: $$ C = \frac {Q}{m\times\Delta T} $$

Whereas:

- \(C\) is representing the specific heat capacity
- \(Q\) is representing the induced thermal energy
- \(m\) is representing the mass
- \(\Delta T\) is the temperature difference
- \(J\) is Joule
- \(°C\) is degrees centigrade or Celsius
- \(K\) is Kelvin

**Example:** If you have a \(15 g\) piece of any metal that absorbs \(134 J\) of heat while increasing from \(24.0°C\) to \(62.7°C\). How will you calculate its specific heat?

- Given heat \(q = 134 J\)
- Given mass \(m = 15.0 g\)
- Change in temperature: \(\Delta T = 62.7 – 24.0 = 38.7\)

To find specific heat put the values in above specific heat equation:

\(\frac {q}{m \times \Delta T} = \frac {134}{15 \times 38.7} = 0.231\).

However, a specific heat calculator can assist you in finding the values without any hustle of manual calculations.

With the support of specific heat formula calculation of specific heat is and easy process. Have a look down below and follow some simple steps:

**Step 1:**

First of all, you have to Determine whether you want to warm up the substance or cool it down. Now give the amount of energy supplied as a positive value. While cooling down the sample, you have to give the subtracted energy as a negative value. For instance, say that we want to decrease the taster's thermal energy by \(63,000 J\). Then \(Q\) will be \(-63,000 J\).

**Step 2:**

Now decide the difference of between the initial and final state of the sample. Let’s suppose the difference is \(ΔT = -3 K\) and m is 5 kg.

**Step 3:**

Just put the values in specific heat equations

\( c = Q / (m x ΔT)\).

In this example, it will be equal to

c = \(-63,000 J / (5 kg * -3 K) = 4,200 J/(kg•K)\).

This is the typical heat capacity of water and it can be calculated by specific heat calculator as well in one go.

The online specific heat capacity calculator is helps you to find heat capacity of different substances. Just follow these steps to get the exact results for substances:

**Input:**

- First of all, select the option either you want to find heat energy, specific heat, mass, initial temperature, final temperature of any substance
- Next, select an option wither you need to perform calculations by change of temperature \(ΔT)\) or initial & final temperature
- Now, you can add the values into the designated fields with respect to selected options
- Then, choose the substance like (water, soil, aluminum, asphalt or etc) for which you need to find the specific heat (this field is optional)
- Make a click on the ‘calculate’ button

**Output:** The specific heat calculator calculates:

- Either heat energy, specific heat, mass, initial temperature, or final temperature of a substance
- Specific heat for a given substance
- Formula for the selected option
- Step by step solution by using formula according to the selected option

**Note:** The specific heat capacity calculator supports different units to provides you the accurate results of substances.

High heat capacity of water is because of hydrogen bonding among its molecules. When heat is absorbed in water, bonds of hydrogen brakes and water molecules start moving freely. With the decrease in water temperature, the hydrogen bonds release a significant amount of energy.

Typically, \(250×332 joules\) of energy required to melt the \(200ng\) of ice.

If you want to melt, 1 g of ice at \(0°C\) total \(334 Joules\) of energy are required. It is also called the latent heat of melting. Specific heat calculator can calculate the joules of energy for multiple grams of any substance within few seconds.

From the informational source of Wikipedia: Specific heat capacity

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