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Stoichiometry Calculator

Stoichiometry Calculator

Enter the chemical equation and the calculator will readily calculate the number of reactants and products involved in it.


Enter an Equation

H He
Li Be B C N O F Ne
Na Mg Al Si P S Cl Ar
K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr
Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe
Cs Ba La Hf Ta W Re Os Ir Pt Au Hg TI Pb Bi Po At Rn
Fr Ra Ac Rf Db Sg Bh Hs Mt Ds Rg Cn Nh FI Mc Lv Ts Og
Lanthanoids Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu
Actinoids Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr
SPACE 1 2 3 4 5 6 7 8 9 0 + = CLEAR

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This stoichiometry calculator lets you calculate the relative amounts of reactants and products involved in a chemical reaction.

Our tools helps you to know the exact number of moles or grams of the entities involved in a chemical equation.

What Is Stoichiometry?

In terms of chemistry:

“The technique that helps to calculate the relative amounts of reactants and products in a balanced chemical reaction is known as stoichiometry”

Determining the stoichiometry of chemical reactions aids you to understand the chemistry of any reaction by comparing the amount of all entities present in it.

Stoichiometric Coefficients:

“In balanced chemical reactions, the numbers used to express the quantity of entities are called stoichiometry coefficients.”

Types of Stoichiometry:

Depending upon the concentration of parameters involved in a chemical reaction, following are the types of stoichiometry:

  • Moles To Moles Stoichiometry
  • Mass To Moles or Mass To Mass Stoichiometry

Stoichiometry Example Problems:

Let’s resolve an example to clarify the concept of stoichiometry:

Example # 01:

Suppose you are experiencing a phenomenon like burning of oxygen gas with hydrogen for the formation of water. Now determine the exact mass of oxygen gas that may be required to burn one gram of hydrogen. Also, mention the water mass obtained at the end.


Carrying out stoichiometry conversion as below:

Step # 01:

The balanced chemical stoichiometry equations for the water formation reaction is as follows:

$$ 2H_{2} + O_{2} → 2H_{2}O $$

Step # 02:

Now you need to write the atomic and molecular masses of each and every atom involved in the reaction:

Atomic masses:

Hydrogen = 1

Oxygen = 16

For calculations and steps, tap the atomic mass calculator.

Molecular mass:

\(H_{2}\) = 2

\(O_{2}\) = 32

\(H_{2}O\) = 18

Here with the help of another molecular formula calculator, you can get to know the steps involved in calculating the molecular mass of any compound.

The above information can also be displayed in the following stoichiometry table:

Atomic Mass

Molecular Mass
H = 1

\(H_{2}\) = 2

O = 16

\(O_{2}\) = 32

Molecular Mass of Water = \(H_{2}O\) = 18

Step # 03:

Change the moles of the elements of the reaction equation.

Step # 04:

Now go for determining the actual mass of the compounds:

When 4 grams of the oxygen reacts with the 32 grams of the oxygen, it produces 36 grams of the water molecule. It means that we actually need to burn approximately 1 gram of the hydrogen gas by using the stoichiometry formula.

So at the end, we have:

1 gram of hydrogen reacts with 32/4 = 8 grams of the oxygen

It yields:

Mass of the water produced = 36/4 = 9 grams

How Solution Stoichiometry Calculator Works?

This section of the content is packed with a complete usage guide of this free stoichiometry converter. Let’s go through it together!


  • What you need to do here is to write the chemical reaction of your choice in the designated field. Also, you can load the pre-saved example reaction
  • After you are done with it, it’s time to hot the calculate button


The free stoichiometric equation solver determines the following results:

  • Determines the amount of reactant as well as the products in terms of moles and grams


From the source of Wikipedia: Stoichiometry, Etymology, Converting grams to moles, Molar proportion, Determining amount of product, Stoichiometric ratio, Limiting reagent and percent yield, Stoichiometry matrix

From the source of Khan Academy: Balancing chemical equations, Calculating amounts of reactants and products, Ideal stoichiometry

From the source of Lumen Learning: Reaction Stoichiometry, Moles to Moles, Grams to Moles