Substitution Calculator

The substitution calculator makes the solution of algebraic equations simple and fast by substituting one variable into another equation.

What is the Substitution Method?

“It is a process of algebraic equations do involve gathering one variable value from one and inserting into the other linear equation to find the values of all the variables”

The solution of the system of equations by substitution process provides the simple solution of the linear algebraic variable. It is possible to know the roots “x” and “y” of linear algebraic equations.

Types of Substitution Method:

The substitution method calculator can be used to solve linear equations by substitution with the following major methods:

Algebraic method
Graphical method

The Substitution Steps:

There are 3 basic steps involved in the process:

First, solve by substitution one equation and get the value of the desired variable.
Secondly, plug in the desired variable values in the second equation.
In the third step, substitute the values into the equation to solve the final value of our variables.

Example:

Now solve the system of linear values.

2x + 4y = 4———-(Eq1)

x + y = 3———-(Eq2)

Find values of “x” from the (Eq2) x = 3 – y

Input values of the variable “x” in the (Eq1) 2 ⋅ (3 – 1y) + 4y = 4

Now the value of variables “y” 2y = -2

The value of “y” in (Eq1) y = -1 y = -1 in the 2x + 4 ⋅ (-1) = 4

The value of “x” x = 4 The final values of the “x” and “y” x = 4 , y = -1

Other Examples:

In the substitution methode calculator, take the value of one variable from one to the other.

System of linear equation	Results
x+y=5 ; x+2y=7	x=3, y =2
-x-7y=-1 ; x-2y=-8	x=−6, y=1
2x + y = 7 ;3x - 4y = 1	x=38/11, y=1/11
2x – y = 3 ; x + 2y = 2	x=8/5, y=1/5
x-3y = -43 ; 2x+2y=-41	x=-209/8, y=45/8

You simply cut down the “x” and “y” by making their coefficients the same. You simply cut down the “x” and “y” by making their coefficients the same.

How to Use the Calculator?

The substitution method calculator is efficient in solving a system of equations. Let’s have a look at its working procedure!

Input:

Enter the variables “x”, and “y” in the designated field
Enter the constant values equation “K”
Now calculate

Output:

Variables “x” and “y”
All steps solved

FAQs:

Why Do Need the Substitution of Algebraic Linear Equations?

Implement the substitution process to solve the values of the variables “x” and “y” in a system of linear values. The substitution method calculator with steps elaborates all the steps of the process and the simple for the users

Citation:

From Wikipedia: (logic), Propositional logic From Calc-Workshop: What is the process?