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Select the equation number and enter all coefficients and constant values to simplify the linear equation

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The substitution calculator makes the solution of algebraic equations simple and fast by substituting one variable into another equation.

**“It is a process of algebraic equations do involve gathering one variable value from one and inserting into the other linear equation to find the values of all the variables”**

The solution of the system of equations by substitution process provides the simple solution of the linear algebraic variable. It is possible to know the roots “x” and “y” of linear algebraic equations.

The substitution method calculator can be used to solve linear equations by substitution with the following major methods:

- Algebraic method
- Graphical method

There are 3 basic steps involved in the process:

- First, solve by substitution one equation and get the value of the desired variable.
- Secondly, plug in the desired variable values in the second equation.
- In the third step, substitute the values into the equation to solve the final value of our variables.

Now solve the system of linear values.

2x + 4y = 4———-(Eq1)

x + y = 3———-(Eq2)

Find values of “x” from the (Eq2) x = 3 – y

Input values of the variable “x” in the (Eq1) 2 ⋅ (3 – 1y) + 4y = 4

Now the value of variables “y” 2y = -2

The value of “y” in (Eq1) y = -1 y = -1 in the 2x + 4 ⋅ (-1) = 4

The value of “x” x = 4 The final values of the “x” and “y” x = 4 , y = -1

In the substitution methode calculator, take the value of one variable from one to the other.

System of linear equation |
Results |

x+y=5 ; x+2y=7 | x=3, y =2 |

-x-7y=-1 ; x-2y=-8 | x=−6, y=1 |

2x + y = 7 ;3x - 4y = 1 | x=38/11, y=1/11 |

2x – y = 3 ; x + 2y = 2 | x=8/5, y=1/5 |

x-3y = -43 ; 2x+2y=-41 | x=-209/8, y=45/8 |

You simply cut down the “x” and “y” by making their coefficients the same. You simply cut down the “x” and “y” by making their coefficients the same.

The substitution method calculator is efficient in solving a system of equations. Let’s have a look at its working procedure!

**Input:**

- Enter the variables “x”, and “y” in the designated field
- Enter the constant values equation “K”
- Now calculate

**Output:**

- Variables “x” and “y”
- All steps solved

Implement the substitution process to solve the values of the variables “x” and “y” in a system of linear values. The substitution method calculator with steps elaborates all the steps of the process and the simple for the users

From Wikipedia: (logic), Propositional logic From Calc-Workshop: What is the process?

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